Example entries

On this page I will show you how you're recording. To simplify the game and different situations we introduce some concepts and notation. Assume that the table of 4 players in the following order: A, B, D, E. Knowing on which hand is one of the players can be identified and all the rest. For example, if a player is on the second T T arm (2), on the first hand it is B (1), the third E (3) and the deliverer will player A.
Assigned game denote the number which is equal to the number of necessary bribes, and the figure in brackets would mean the number of missing or taken over playing laid bribes. For example: 6 (0) - 6 taken bribes missing 0; 6 (1) - 6 taken bribes, missing 1; 6 (1) - 7 taken bribes, and VISTA without one.
In connection with the above written, the expression r (2) = 6 (0) means that the player T on the second hand named sixfold game and took as much as assigned - 6 bribes. If one of the whist whist, and the other passes, this situation is denoted by E (+), respectively, Player B folds. It is obvious that all the bribes will belong to the player E, except for harness play when bribes are divided equally, and their number is unknown. When VISTA two players, you need to specify how many who took bribes. For example: E = 3 - E player took three bribes; B = 1 - Player B took a bribe.
The presence in the Widow tricks denoted A = 2 - as the player A in this case is deliverer. The two community cards bribes.
Expression of E (=) means that the player has left E "for its" at the same time the number of tricks that took playing, is not indicated: r (2) = 6; E (=). For example, the record r (2) = 6 (0), E (=), B (+) means that after the announcement of the E "for his" B play back.
Raspasovki written as follows: A = 0 + 4 + 5, that means if player A hand played raspasovka, the first arm (B) did not take bribes, second hand (D) took 4 bribe, the third arm (E) 5 took bribes. It follows that the deliverer has taken a bribe.
To in any way to learn what was written above, we explain an example 4.

A (1) = 7 (1), B = 1, D = 1

This entry means that player A on the first hand appointed semernuyu game and took 8 tricks. Players B and D vistovali and took on a bribe. Deliverer player was E. The community cards were not bribes. Player A writes a bullet at a rate of 40. Players B and D are recorded on it for 4 whist.

B (2) = 8 (+2), T (), E = 2

Player B on the second hand named eightfold game and took all 10 tricks, so he writes a bullet 60. T Player vistoval never took any bribes so his record - 30 on the mountain. The community cards were two bribes. Deliverer E records to player B 12 whist.

E (3) = 6 (-2), B (+)

Player E on the third hand appointed gears and left without the two, so he writes 40 on the mountain. As the player T pass, he, along with the player B says whist whist half 10 each. Deliverers A player writes on E Consolation - 4 whist.

T (2) = 6 (-1), E (=), A (+)

Player T on the second hand named sixfold game and was left without a bribe, for which he wrote the mountain 20. VISTA Player E tried to leave "for their" second vist and player B has agreed to it. However, A deliverer back and won the game. Now, the player says Mr. whist he alone. Total 16 whist.

Now consider the following series 25 games.

1 B (1) = 8 (1), D (+) and A = 1
2. B = 3 + 3 + 2
3. A (2) = M (2) - Misery received two bribes
4. D (3) = 10 (0)
5. E (3) = 7 (0), B = 2, D = 1
6. E (2) = 6 (1), A = 2, D = 1
7. A (2) = 8 (0), B (+)
8. A (1) = 6, D (=)
9. r (2) = 6 (0), E = 3, B = 1
10. B = 5 + 2 + 3
11. E (1) = 9 and D = - two pass
12. D (3) = 7 (-1), A (1)
13. A = 3 + 6 + 0
14. F (1) = 7 (0), E (+)
15. E (1) = 8 (0), B (+)
16. D (2) = 6 (0), T (=), and E (+)
17. B (1) = M (0)
18 A (3) = 7 (1), r = 1, E = 1
19. A (2) = 9 (0), E (+)
20. E = 1 + 3 + 4
21. E (3) = 6 (-1), D (+)
22. E (2) = 6 (1), A = 2, D = 1
23. T = 4 + 2 + 4
24. D (2) = 6 (-1), T = 4, k = 1
25. E (3) = 6, D (=)

Imagine the results of these games in the form in which we have described in the figure, which is lower.

In the first game the player B on the first hand appointed eightfold game and took bribes 9. The bullet, he recorded 60 points. Player D vistoval and took a bribe, thus qualifying for a record six whist. In A deliverer in the Widow was a bribe, for which he recorded on playing whist 6. All these records are in the picture circled. Check the remaining recording, you can manually than most potreniruetes read the record.
In the figure you can see the post in the center circle, where the game was short and 800 (4 bullets, 200). After the 25th game in the sum has to be 810 (170 + 25 + 200 + 190). All the game is over. Can begin summing the results according to the procedure that was described earlier.
Player A in exactly 200 pulque, so it does not make action on the removal of the mountain and the mountain of cheating. Player B makes the mount 10. The player brings to the F mount 30. Player E withdraws from the mount 50. Minimum mountain is the player E. Subtract this mountain from all the rest and divide the resulting residue on 4. Division needs to be done to the nearest whole number downwards. The result is that the player A should all be written on Vista 52, the player B to 17 whist, the player on the T 47 whist. The same should be done and the player E.
If the player should write to Mr. Player A - 52 whist, and player A to player D - 47 whist, for simplicity can be written on the player's A - 5 whist. You can also enroll in similar other cases. After the mountain will be separated, made a mutual settlement between the players of whist. So Player A player has lost £ 54 vista. Then adding individual wins and losses, we obtain the final result: the player A and player D lost 99 and 85, respectively, whist; Player B and Player E have won 72 and 11 of whist.
The sprawling present recording 5k, which means that for whist given by 5 cents. Accordingly, it will be simple to calculate gains and losses of each player.
Note: I want to note that to date, sometimes for brevity zeros in pulque and grief are not written, but we have in mind. For example, the pinion game prize and a penalty is 2, and 4, and so on semernoy

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